Q.1 A train ,130 meters long travels at a speed of 45 km/hr crosses a bridge in 30 seconds. The length of the bridge is
A. 9(3/5) days B. 9(1/5) days
C. 9(2/5) days D. 10 days
A. 8.2 B. 4.2
C. 6.1 D. 7.2
A. 8% B. 6%
C. 4% D. 7%
A. 23 years B. 22 years
C. 21 years D. 20 years
10 × 3.2 = 32
Total runs = 282
Remaining runs to be scored = 282 -
32 = 250
Remaining overs = 40
Run rate needed =250/40 =6.25
A. 270 m B. 245 m
C. 235 m D. 220 m
Q.2 P can lay railway track between two stations in 16 days. Q can do the same job in 12 days. With the help of R, they completes the job in 4 days. How much days does it take for R alone to complete the work?
C. 9(2/5) days D. 10 days
Q.3 A person crosses a 600 m long street in 5 minutes. What is his speed in km per hour?
C. 6.1 D. 7.2
Q.4 Arun took a loan of Rs. 1400 with simple interest for as many years as the rate of interest. If he paid Rs.686 as interest at the end of the loan period, what was the rate of interest?
C. 4% D. 7%
Q.5 Insert the missing number. 34, 7, 37, 14, 40, 28, 43, (...)
A. 31 B. 42
C. 46 D. 56
C. 46 D. 56
Q.6 A die is rolled twice. What is the probability of getting a sum equal to 9?
A 1/3 B 2/3
C 1/9 D 2/9
Q.7 X starts a business with Rs.45000. Y joins in the business after 3 months with Rs.30000. What will be the ratio in which they should share the profit at the end of the year?
A. 1:2 B. 2:1
C. 1:3 D. 3:1
A. 1:2 B. 2:1
C. 1:3 D. 3:1
Q.8 A man is 24 years older than his son. In two years, his age will be twice the age of his son. What is the present age of his son?
C. 21 years D. 20 years
Q.9 In the first 10 overs of a cricket game, the run rate was only 3.2. What should be the run rate in the remaining 40 overs to reach the target of 282 runs?
A. 6.25 B. 5.5
C. 7.4 D. 5
C. 7.4 D. 5
Q.10 What is the greatest number of four digits which is divisible by 15, 25, 40 and 75 ?
A. 9800 B. 9600
C. 9400 D. 9200
C. 9400 D. 9200
Answers
1.Ans- B
Explanation :
Assume the length of the bridge = x
meter
Total distance covered = 130+x
meter
total time taken = 30s
speed = Total distance covered /total
time taken = (130+x)/30 m/s
=> 45 × (10/36) = (130+x)/30
=> 45 × 10 × 30 /36 = 130+x
=> 45 × 10 × 10 / 12 = 130+x
=> 15 × 10 × 10 / 4 = 130+x
=> 15 × 25 = 130+x = 375
=> x = 375-130 =245
Assume the length of the bridge = x
meter
Total distance covered = 130+x
meter
total time taken = 30s
speed = Total distance covered /total
time taken = (130+x)/30 m/s
=> 45 × (10/36) = (130+x)/30
=> 45 × 10 × 30 /36 = 130+x
=> 45 × 10 × 10 / 12 = 130+x
=> 15 × 10 × 10 / 4 = 130+x
=> 15 × 25 = 130+x = 375
=> x = 375-130 =245
2.Ans- A
Amount of work P can do in 1 day =
1/16
Amount of work Q can do in 1 day =
1/12
Amount of work P, Q and R can
together do in 1 day = 1/4
Amount of work R can do in 1 day =
1/4 - (1/16 + 1/12) = 3/16 – 1/12 =
5/48
=> Hence R can do the job on 48/5
days = 9 (3/5) days
1/16
Amount of work Q can do in 1 day =
1/12
Amount of work P, Q and R can
together do in 1 day = 1/4
Amount of work R can do in 1 day =
1/4 - (1/16 + 1/12) = 3/16 – 1/12 =
5/48
=> Hence R can do the job on 48/5
days = 9 (3/5) days
3.Ans- D
Explanation :
distance = 600 meter
time = 5 minutes = 5 x 60 seconds =
300 seconds
speed := 600/300 = 2 m/s
distance = 600 meter
time = 5 minutes = 5 x 60 seconds =
300 seconds
speed := 600/300 = 2 m/s
4.Ans- D
Explanation :
Let rate = R%
Then, Time, T = R years
P = Rs.1400
SI = Rs.686
(686*100)/1400 = R^2
R^2 = 49
R = 7%
Let rate = R%
Then, Time, T = R years
P = Rs.1400
SI = Rs.686
(686*100)/1400 = R^2
R^2 = 49
R = 7%
5.Ans- D
Explanation :
We have two series here
34, 37, 40, 43, ... (Increase by 3)
7, 14, 28, ... (Multiply by 2)
Hence, next term is 28 × 2 = 56
We have two series here
34, 37, 40, 43, ... (Increase by 3)
7, 14, 28, ... (Multiply by 2)
Hence, next term is 28 × 2 = 56
6.Ans- C
Explanation :
Total number of outcomes possible
when a die is rolled = 6 (∵ any one
face out of the 6 faces)
Hence, total number of outcomes
possible when a die is rolled twice,
n(S) = 6 × 6 = 36
E = Getting a sum of 9 when the two
dice fall = {(3, 6), {4, 5}, {5, 4}, (6,
3)}
Hence, n(E) = 4
P(E)=n(E)/n(S) = 9/36 = 1/9
Total number of outcomes possible
when a die is rolled = 6 (∵ any one
face out of the 6 faces)
Hence, total number of outcomes
possible when a die is rolled twice,
n(S) = 6 × 6 = 36
E = Getting a sum of 9 when the two
dice fall = {(3, 6), {4, 5}, {5, 4}, (6,
3)}
Hence, n(E) = 4
P(E)=n(E)/n(S) = 9/36 = 1/9
7.Ans- B
Explanation :
Ratio in which they should share the
profit
= Ratio of the investments
multiplied by the time period
= 45000 * 12: 30000 * 9
= 45 * 12: 30 * 9
= 3*12: 2 * 9
= 2:1
Ratio in which they should share the
profit
= Ratio of the investments
multiplied by the time period
= 45000 * 12: 30000 * 9
= 45 * 12: 30 * 9
= 3*12: 2 * 9
= 2:1
8.Ans- B
Explanation:
Let the present age of the son = x
years
Then present age the man = (x+24)
years
Given that in 2 years, man's age
will be twice the age of his son
=> (x+24) +2 = 2(x+2)
=> x = 22
Let the present age of the son = x
years
Then present age the man = (x+24)
years
Given that in 2 years, man's age
will be twice the age of his son
=> (x+24) +2 = 2(x+2)
=> x = 22
9.Ans- A
Explanation:
Runs scored in the first 10 overs =10 × 3.2 = 32
Total runs = 282
Remaining runs to be scored = 282 -
32 = 250
Remaining overs = 40
Run rate needed =250/40 =6.25
10.Ans- B
Explanation :
Greatest number of four digits =
9999
LCM of 15, 25, 40 and 75 = 600
9999 ÷ 600 = 16, remainder = 399
Hence, greatest number of four digits
which is divisible by 15, 25, 40 and
75
= 9999 - 399 = 9600
Greatest number of four digits =
9999
LCM of 15, 25, 40 and 75 = 600
9999 ÷ 600 = 16, remainder = 399
Hence, greatest number of four digits
which is divisible by 15, 25, 40 and
75
= 9999 - 399 = 9600
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